# C++ string compare() VS ==

C++ string compare() 和 == 操作符号比较

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C++ string compare() 和 == 操作符号比较

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LeetCode Recover Binary Search Tree: Find the inverse pair in the inorder traversal with O(1) Space by the so called Morris Traversal and swap the inverse pair

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LeetCode Binary Tree Maximum Path Sum: DFS scan tree to get two local/global maximum path for each node, values for root node can be calculated with DP.

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leetcode: Surrounded Regions solution

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To solve LeetCode Permutation Sequence, math could be adopted to identify the correct number in the corresponding position rather than do DFS simulation.

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