# leetcode: Wildcard Matching

#### Wildcard Matching Problem Description:

Implement wildcard pattern matching with support for `'?'` and `'*'`.

```'?' Matches any single character.
'*' Matches any sequence of characters (including the empty sequence).

The matching should cover the entire input string (not partial).

The function prototype should be:
bool isMatch(const char *s, const char *p)

Some examples:
isMatch("aa","a") ? false
isMatch("aa","aa") ? true
isMatch("aaa","aa") ? false
isMatch("aa", "*") ? true
isMatch("aa", "a*") ? true
isMatch("ab", "?*") ? true
isMatch("aab", "c*a*b") ? false```

#### Wildcard Matching Solution and Precautions:

(1) recursive solution or DP, F(i, j) denote if s[0]…s[i-1] and p[0]…p[j-1] is matched or not

F(i, j) = (s[i-1] == p[j-1]) && F(i-1, j-1) if  p[j-1] != ‘*’ or ‘?’
F(i, j) = F(i-1, j-1)  if  p[j] == ‘?’
F(i, j) = OR F(i-l, j-1) for l = 0, … i,  if  p[j] == ‘*’

(2) greedy: whenever encounter ‘*’ in p, keep record of the current position of ‘*’ in p and the current index in s. Try to match the stuff behind this ‘*’ in p with s, if not matched, just s++ and then try to match again.

#### Wildcard Matching Tips and Divergent thinking:

The dp version need to do memory optimization, otherwise OJ will report memory limit exceeds. Usually, only the greedy approach could pass OJ, the maximum size of the test case in OJ is around 30000^2.

Written on June 23, 2013